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2031254145013 is a prime number
BaseRepresentation
bin11101100011110000001…
…011101000011111110101
321012012000121000220212111
4131203300023220133311
5231240002030120023
64153051213451021
7266516241232252
oct35436013503765
97165017026774
102031254145013
117134a50125a5
12289806aa0a71
131197146ca8c2
14704556c0429
1537c86c8a00d
hex1d8f02e87f5

2031254145013 has 2 divisors, whose sum is σ = 2031254145014. Its totient is φ = 2031254145012.

The previous prime is 2031254144999. The next prime is 2031254145017. The reversal of 2031254145013 is 3105414521302.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1894526510724 + 136727634289 = 1376418^2 + 369767^2 .

It is a cyclic number.

It is not a de Polignac number, because 2031254145013 - 229 = 2030717274101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2031254145017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015627072506 + 1015627072507.

It is an arithmetic number, because the mean of its divisors is an integer number (1015627072507).

Almost surely, 22031254145013 is an apocalyptic number.

It is an amenable number.

2031254145013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2031254145013 is an equidigital number, since it uses as much as digits as its factorization.

2031254145013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 2031254145013 its reverse (3105414521302), we get a palindrome (5136668666315).

The spelling of 2031254145013 in words is "two trillion, thirty-one billion, two hundred fifty-four million, one hundred forty-five thousand, thirteen".