Base | Representation |
---|---|
bin | 1001001111001100010111… |
… | …01001010101010111000111 |
3 | 2122220221000211211100220211 |
4 | 10213212023221111113013 |
5 | 10130303010230224312 |
6 | 111111435231140251 |
7 | 4164404050260412 |
oct | 447461351252707 |
9 | 78827024740824 |
10 | 20313243211207 |
11 | 6521886255991 |
12 | 2340a14074687 |
13 | b446b89ba99b |
14 | 503248158b79 |
15 | 2535d9ed93a7 |
hex | 12798ba555c7 |
20313243211207 has 2 divisors, whose sum is σ = 20313243211208. Its totient is φ = 20313243211206.
The previous prime is 20313243211187. The next prime is 20313243211223. The reversal of 20313243211207 is 70211234231302.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20313243211207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20313243215207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10156621605603 + 10156621605604.
It is an arithmetic number, because the mean of its divisors is an integer number (10156621605604).
Almost surely, 220313243211207 is an apocalyptic number.
20313243211207 is a deficient number, since it is larger than the sum of its proper divisors (1).
20313243211207 is an equidigital number, since it uses as much as digits as its factorization.
20313243211207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 20313243211207 its reverse (70211234231302), we get a palindrome (90524477442509).
The spelling of 20313243211207 in words is "twenty trillion, three hundred thirteen billion, two hundred forty-three million, two hundred eleven thousand, two hundred seven".
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