Search a number
-
+
2031411323041 is a prime number
BaseRepresentation
bin11101100011111001100…
…011001110000010100001
321012012102112210101120221
4131203321203032002201
5231240312244314131
64153114550403041
7266523160226242
oct35437143160241
97165375711527
102031411323041
117135758077a1
1228984b660481
1311973b140a59
147046c516cc9
1537c95986411
hex1d8f98ce0a1

2031411323041 has 2 divisors, whose sum is σ = 2031411323042. Its totient is φ = 2031411323040.

The previous prime is 2031411323023. The next prime is 2031411323057. The reversal of 2031411323041 is 1403231141302.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1418159448225 + 613251874816 = 1190865^2 + 783104^2 .

It is a cyclic number.

It is not a de Polignac number, because 2031411323041 - 235 = 1997051584673 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2031411322997 and 2031411323015.

It is not a weakly prime, because it can be changed into another prime (2031411323021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015705661520 + 1015705661521.

It is an arithmetic number, because the mean of its divisors is an integer number (1015705661521).

Almost surely, 22031411323041 is an apocalyptic number.

It is an amenable number.

2031411323041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2031411323041 is an equidigital number, since it uses as much as digits as its factorization.

2031411323041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 2031411323041 its reverse (1403231141302), we get a palindrome (3434642464343).

The spelling of 2031411323041 in words is "two trillion, thirty-one billion, four hundred eleven million, three hundred twenty-three thousand, forty-one".