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20314131113131 is a prime number
BaseRepresentation
bin1001001111001110000001…
…00100011010010010101011
32122221000022201120110101021
410213213000210122102223
510130311320031110011
6111112103310033311
74164435051310642
oct447470044322253
978830281513337
1020314131113131
1165221a1474829
1223410214a8837
13b447ca93983b
145032d0046359
1525363ce26471
hex1279c091a4ab

20314131113131 has 2 divisors, whose sum is σ = 20314131113132. Its totient is φ = 20314131113130.

The previous prime is 20314131113117. The next prime is 20314131113201. The reversal of 20314131113131 is 13131113141302.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20314131113131 - 229 = 20313594242219 is a prime.

It is a super-2 number, since 2×203141311131312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20314131113096 and 20314131113105.

It is not a weakly prime, because it can be changed into another prime (20314131413131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10157065556565 + 10157065556566.

It is an arithmetic number, because the mean of its divisors is an integer number (10157065556566).

Almost surely, 220314131113131 is an apocalyptic number.

20314131113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

20314131113131 is an equidigital number, since it uses as much as digits as its factorization.

20314131113131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 20314131113131 its reverse (13131113141302), we get a palindrome (33445244254433).

The spelling of 20314131113131 in words is "twenty trillion, three hundred fourteen billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred thirty-one".