Base | Representation |
---|---|
bin | 1001001111001110000001… |
… | …00100011010010010101011 |
3 | 2122221000022201120110101021 |
4 | 10213213000210122102223 |
5 | 10130311320031110011 |
6 | 111112103310033311 |
7 | 4164435051310642 |
oct | 447470044322253 |
9 | 78830281513337 |
10 | 20314131113131 |
11 | 65221a1474829 |
12 | 23410214a8837 |
13 | b447ca93983b |
14 | 5032d0046359 |
15 | 25363ce26471 |
hex | 1279c091a4ab |
20314131113131 has 2 divisors, whose sum is σ = 20314131113132. Its totient is φ = 20314131113130.
The previous prime is 20314131113117. The next prime is 20314131113201. The reversal of 20314131113131 is 13131113141302.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20314131113131 - 229 = 20313594242219 is a prime.
It is a super-2 number, since 2×203141311131312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20314131113096 and 20314131113105.
It is not a weakly prime, because it can be changed into another prime (20314131413131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10157065556565 + 10157065556566.
It is an arithmetic number, because the mean of its divisors is an integer number (10157065556566).
Almost surely, 220314131113131 is an apocalyptic number.
20314131113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20314131113131 is an equidigital number, since it uses as much as digits as its factorization.
20314131113131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 20314131113131 its reverse (13131113141302), we get a palindrome (33445244254433).
The spelling of 20314131113131 in words is "twenty trillion, three hundred fourteen billion, one hundred thirty-one million, one hundred thirteen thousand, one hundred thirty-one".
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