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20334412332539 is a prime number
BaseRepresentation
bin1001001111110011110010…
…11011000111110111111011
32122222221200011021011010122
410213321321123013313323
510131124334024120124
6111125300003003455
74166053456654334
oct447717133076773
978887604234118
1020334412332539
11652a859710088
122344b4166958b
13b466b0667b96
1450429581328b
15253e286e175e
hex127e796c7dfb

20334412332539 has 2 divisors, whose sum is σ = 20334412332540. Its totient is φ = 20334412332538.

The previous prime is 20334412332461. The next prime is 20334412332541. The reversal of 20334412332539 is 93523321443302.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20334412332539 is a prime.

It is a super-3 number, since 3×203344123325393 (a number of 41 digits) contains 333 as substring.

Together with 20334412332541, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20334412332539.

It is not a weakly prime, because it can be changed into another prime (20334412332569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10167206166269 + 10167206166270.

It is an arithmetic number, because the mean of its divisors is an integer number (10167206166270).

Almost surely, 220334412332539 is an apocalyptic number.

20334412332539 is a deficient number, since it is larger than the sum of its proper divisors (1).

20334412332539 is an equidigital number, since it uses as much as digits as its factorization.

20334412332539 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1399680, while the sum is 44.

The spelling of 20334412332539 in words is "twenty trillion, three hundred thirty-four billion, four hundred twelve million, three hundred thirty-two thousand, five hundred thirty-nine".