Base | Representation |
---|---|
bin | 101110001111111010110110… |
… | …111111111010110100111111 |
3 | 222200012020121122110020122011 |
4 | 232033322312333322310333 |
5 | 203130033130120211221 |
6 | 2000334322403432051 |
7 | 60562314665024443 |
oct | 5617726677726477 |
9 | 880166548406564 |
10 | 203404131413311 |
11 | 598a12314a2394 |
12 | 1a991100085627 |
13 | 8965c0934067a |
14 | 3832b53680823 |
15 | 187b01cc5e1e1 |
hex | b8feb6ffad3f |
203404131413311 has 2 divisors, whose sum is σ = 203404131413312. Its totient is φ = 203404131413310.
The previous prime is 203404131413293. The next prime is 203404131413347. The reversal of 203404131413311 is 113314131404302.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 203404131413311 - 25 = 203404131413279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (203404131413381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101702065706655 + 101702065706656.
It is an arithmetic number, because the mean of its divisors is an integer number (101702065706656).
Almost surely, 2203404131413311 is an apocalyptic number.
203404131413311 is a deficient number, since it is larger than the sum of its proper divisors (1).
203404131413311 is an equidigital number, since it uses as much as digits as its factorization.
203404131413311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 203404131413311 its reverse (113314131404302), we get a palindrome (316718262817613).
Subtracting from 203404131413311 its reverse (113314131404302), we obtain a palindrome (90090000009009).
The spelling of 203404131413311 in words is "two hundred three trillion, four hundred four billion, one hundred thirty-one million, four hundred thirteen thousand, three hundred eleven".
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