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20341213125 = 35410848647
BaseRepresentation
bin10010111100011011…
…100100011111000101
31221111121120200122220
4102330123210133011
5313124322310000
613202234442553
71320034313232
oct227433443705
957447520586
1020341213125
1186990a2542
123b38293459
131bc22a54ac
14dad746789
157e0bbb1a0
hex4bc6e47c5

20341213125 has 20 divisors (see below), whose sum is σ = 33891176352. Its totient is φ = 10848646000.

The previous prime is 20341213103. The next prime is 20341213153. The reversal of 20341213125 is 52131214302.

It is not a de Polignac number, because 20341213125 - 25 = 20341213093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20341213095 and 20341213104.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 5422449 + ... + 5426198.

Almost surely, 220341213125 is an apocalyptic number.

20341213125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

It is an amenable number.

20341213125 is a deficient number, since it is larger than the sum of its proper divisors (13549963227).

20341213125 is an equidigital number, since it uses as much as digits as its factorization.

20341213125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10848670 (or 10848655 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 20341213125 its reverse (52131214302), we get a palindrome (72472427427).

The spelling of 20341213125 in words is "twenty billion, three hundred forty-one million, two hundred thirteen thousand, one hundred twenty-five".

Divisors: 1 3 5 15 25 75 125 375 625 1875 10848647 32545941 54243235 162729705 271216175 813648525 1356080875 4068242625 6780404375 20341213125