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203414041111 is a prime number
BaseRepresentation
bin1011110101110001101…
…0111111001000010111
3201110001021101221110111
42331130122333020113
511313042443303421
6233240324503451
720460534551431
oct2753432771027
9643037357414
10203414041111
11792a3a17886
123350ab4ab87
1316249720048
149bb96a5651
155458051ee1
hex2f5c6bf217

203414041111 has 2 divisors, whose sum is σ = 203414041112. Its totient is φ = 203414041110.

The previous prime is 203414041099. The next prime is 203414041139. The reversal of 203414041111 is 111140414302.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 203414041111 - 211 = 203414039063 is a prime.

It is a super-2 number, since 2×2034140411112 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (203414044111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101707020555 + 101707020556.

It is an arithmetic number, because the mean of its divisors is an integer number (101707020556).

Almost surely, 2203414041111 is an apocalyptic number.

203414041111 is a deficient number, since it is larger than the sum of its proper divisors (1).

203414041111 is an equidigital number, since it uses as much as digits as its factorization.

203414041111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 203414041111 its reverse (111140414302), we get a palindrome (314554455413).

The spelling of 203414041111 in words is "two hundred three billion, four hundred fourteen million, forty-one thousand, one hundred eleven".