Base | Representation |
---|---|
bin | 11101100110101000001… |
… | …000111011001111111011 |
3 | 21012110222200110002222012 |
4 | 131212220020323033323 |
5 | 231312312123140011 |
6 | 4154321343520135 |
7 | 266655565312043 |
oct | 35465010731773 |
9 | 7173880402865 |
10 | 2034340443131 |
11 | 714839165aa7 |
12 | 28a3285b904b |
13 | 119ab6c390c9 |
14 | 7066954c723 |
15 | 37db7bc8a8b |
hex | 1d9a823b3fb |
2034340443131 has 2 divisors, whose sum is σ = 2034340443132. Its totient is φ = 2034340443130.
The previous prime is 2034340443077. The next prime is 2034340443173. The reversal of 2034340443131 is 1313440434302.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2034340443131 - 230 = 2033266701307 is a prime.
It is a super-2 number, since 2×20343404431312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2034340443931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1017170221565 + 1017170221566.
It is an arithmetic number, because the mean of its divisors is an integer number (1017170221566).
Almost surely, 22034340443131 is an apocalyptic number.
2034340443131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2034340443131 is an equidigital number, since it uses as much as digits as its factorization.
2034340443131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 2034340443131 its reverse (1313440434302), we get a palindrome (3347780877433).
The spelling of 2034340443131 in words is "two trillion, thirty-four billion, three hundred forty million, four hundred forty-three thousand, one hundred thirty-one".
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