Base | Representation |
---|---|
bin | 1001010000001010001111… |
… | …00110101011010110110111 |
3 | 2200001002202212201022212221 |
4 | 10220011013212223112313 |
5 | 10131324023104340201 |
6 | 111135011344223211 |
7 | 4166661165243334 |
oct | 450050746532667 |
9 | 80032685638787 |
10 | 20346461402551 |
11 | 6534982037789 |
12 | 234734490ab07 |
13 | b47880a206cb |
14 | 504ab9b6598b |
15 | 2543d14064a1 |
hex | 1281479ab5b7 |
20346461402551 has 2 divisors, whose sum is σ = 20346461402552. Its totient is φ = 20346461402550.
The previous prime is 20346461402543. The next prime is 20346461402669. The reversal of 20346461402551 is 15520416464302.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20346461402551 - 23 = 20346461402543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20346461402498 and 20346461402507.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20346461492551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10173230701275 + 10173230701276.
It is an arithmetic number, because the mean of its divisors is an integer number (10173230701276).
Almost surely, 220346461402551 is an apocalyptic number.
20346461402551 is a deficient number, since it is larger than the sum of its proper divisors (1).
20346461402551 is an equidigital number, since it uses as much as digits as its factorization.
20346461402551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 43.
Adding to 20346461402551 its reverse (15520416464302), we get a palindrome (35866877866853).
The spelling of 20346461402551 in words is "twenty trillion, three hundred forty-six billion, four hundred sixty-one million, four hundred two thousand, five hundred fifty-one".
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