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2034744220133 is a prime number
BaseRepresentation
bin11101100111000000001…
…101001101100111100101
321012112000211020002212222
4131213000031031213211
5231314124010021013
64154425410122125
7300001600334342
oct35470015154745
97175024202788
102034744220133
11714a260806a9
1228a41b880345
13119b4c7a0901
14706a70177c9
1537ddd386508
hex1d9c034d9e5

2034744220133 has 2 divisors, whose sum is σ = 2034744220134. Its totient is φ = 2034744220132.

The previous prime is 2034744220099. The next prime is 2034744220183. The reversal of 2034744220133 is 3310224474302.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1552062489124 + 482681731009 = 1245818^2 + 694753^2 .

It is a cyclic number.

It is not a de Polignac number, because 2034744220133 - 238 = 1759866313189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2034744220093 and 2034744220102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2034744220183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1017372110066 + 1017372110067.

It is an arithmetic number, because the mean of its divisors is an integer number (1017372110067).

Almost surely, 22034744220133 is an apocalyptic number.

It is an amenable number.

2034744220133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2034744220133 is an equidigital number, since it uses as much as digits as its factorization.

2034744220133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 35.

Adding to 2034744220133 its reverse (3310224474302), we get a palindrome (5344968694435).

The spelling of 2034744220133 in words is "two trillion, thirty-four billion, seven hundred forty-four million, two hundred twenty thousand, one hundred thirty-three".