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203500145100983 is a prime number
BaseRepresentation
bin101110010001010100010001…
…110111000100100010110111
3222200112102110000010221101112
4232101110101313010202313
5203133121244121212413
62000450402010145235
760602254205635223
oct5621242167044267
9880472400127345
10203500145100983
1159928a21742a95
121a9a7836a2221b
138971c9b011903
143837661111783
15187d78c0292a8
hexb91511dc48b7

203500145100983 has 2 divisors, whose sum is σ = 203500145100984. Its totient is φ = 203500145100982.

The previous prime is 203500145100943. The next prime is 203500145101021. The reversal of 203500145100983 is 389001541005302.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 203500145100983 - 210 = 203500145099959 is a prime.

It is a super-2 number, since 2×2035001451009832 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 203500145100983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (203500145100943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101750072550491 + 101750072550492.

It is an arithmetic number, because the mean of its divisors is an integer number (101750072550492).

Almost surely, 2203500145100983 is an apocalyptic number.

203500145100983 is a deficient number, since it is larger than the sum of its proper divisors (1).

203500145100983 is an equidigital number, since it uses as much as digits as its factorization.

203500145100983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 203500145100983 in words is "two hundred three trillion, five hundred billion, one hundred forty-five million, one hundred thousand, nine hundred eighty-three".