Base | Representation |
---|---|
bin | 11101101100000000001… |
… | …010110111001010111001 |
3 | 21020000212221020110221221 |
4 | 131230000022313022321 |
5 | 231411122223004032 |
6 | 4201114211032041 |
7 | 300251612353042 |
oct | 35540012671271 |
9 | 7200787213857 |
10 | 2040112313017 |
11 | 7172302402a9 |
12 | 28b47959b621 |
13 | 11a4c697ba2c |
14 | 70a55d358c9 |
15 | 3810479c597 |
hex | 1db002b72b9 |
2040112313017 has 2 divisors, whose sum is σ = 2040112313018. Its totient is φ = 2040112313016.
The previous prime is 2040112313009. The next prime is 2040112313053. The reversal of 2040112313017 is 7103132110402.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2038667096761 + 1445216256 = 1427819^2 + 38016^2 .
It is a cyclic number.
It is not a de Polignac number, because 2040112313017 - 23 = 2040112313009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2040112312982 and 2040112313000.
It is not a weakly prime, because it can be changed into another prime (2040112313117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1020056156508 + 1020056156509.
It is an arithmetic number, because the mean of its divisors is an integer number (1020056156509).
Almost surely, 22040112313017 is an apocalyptic number.
It is an amenable number.
2040112313017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2040112313017 is an equidigital number, since it uses as much as digits as its factorization.
2040112313017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 2040112313017 its reverse (7103132110402), we get a palindrome (9143244423419).
The spelling of 2040112313017 in words is "two trillion, forty billion, one hundred twelve million, three hundred thirteen thousand, seventeen".
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