Search a number
-
+
204014043351 = 32192295209889
BaseRepresentation
bin1011111000000000101…
…1110100000011010111
3201111121002102012210200
42332000023310003113
511320310043341401
6233420040551543
720511441520206
oct2760013640327
9644532365720
10204014043351
11795816773a8
1233657a825b3
1316313b19961
149c3524d23d
155490a70686
hex2f802f40d7

204014043351 has 24 divisors (see below), whose sum is σ = 311551422000. Its totient is φ = 128288282112.

The previous prime is 204014043349. The next prime is 204014043397. The reversal of 204014043351 is 153340410402.

It is a happy number.

204014043351 is a `hidden beast` number, since 2 + 0 + 40 + 140 + 433 + 51 = 666.

It is not a de Polignac number, because 204014043351 - 21 = 204014043349 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (204014041351) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2565786 + ... + 2644103.

It is an arithmetic number, because the mean of its divisors is an integer number (12981309250).

Almost surely, 2204014043351 is an apocalyptic number.

204014043351 is a deficient number, since it is larger than the sum of its proper divisors (107537378649).

204014043351 is a wasteful number, since it uses less digits than its factorization.

204014043351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5210143 (or 5210140 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 27.

Adding to 204014043351 its reverse (153340410402), we get a palindrome (357354453753).

The spelling of 204014043351 in words is "two hundred four billion, fourteen million, forty-three thousand, three hundred fifty-one".

Divisors: 1 3 9 19 57 171 229 687 2061 4351 13053 39159 5209889 15629667 46889001 98987891 296963673 890891019 1193064581 3579193743 10737581229 22668227039 68004681117 204014043351