Base | Representation |
---|---|
bin | 1001010001110100001101… |
… | …00101001010101101001101 |
3 | 2200020112121201102212100120 |
4 | 10220322012211022231031 |
5 | 10133242031222434000 |
6 | 111221100515015153 |
7 | 4204044045055563 |
oct | 450720645125515 |
9 | 80215551385316 |
10 | 20403352546125 |
11 | 6557016663a0a |
12 | 235638159a4b9 |
13 | b50049371683 |
14 | 507755797a33 |
15 | 255b10c616a0 |
hex | 128e8694ab4d |
20403352546125 has 32 divisors (see below), whose sum is σ = 33959662568832. Its totient is φ = 10879068816000.
The previous prime is 20403352546103. The next prime is 20403352546127. The reversal of 20403352546125 is 52164525330402.
It is not a de Polignac number, because 20403352546125 - 221 = 20403350448973 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20403352546127) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5294896 + ... + 8297145.
It is an arithmetic number, because the mean of its divisors is an integer number (1061239455276).
Almost surely, 220403352546125 is an apocalyptic number.
20403352546125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
20403352546125 is a deficient number, since it is larger than the sum of its proper divisors (13556310022707).
20403352546125 is a wasteful number, since it uses less digits than its factorization.
20403352546125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13596062 (or 13596052 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 20403352546125 its reverse (52164525330402), we get a palindrome (72567877876527).
The spelling of 20403352546125 in words is "twenty trillion, four hundred three billion, three hundred fifty-two million, five hundred forty-six thousand, one hundred twenty-five".
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