Base | Representation |
---|---|
bin | 11101101100010011101… |
… | …110001111101001010101 |
3 | 21020001201210111202112022 |
4 | 131230103232033221111 |
5 | 231412310212333123 |
6 | 4201210530102525 |
7 | 300263004565625 |
oct | 35542356175125 |
9 | 7201653452468 |
10 | 2040440355413 |
11 | 717389428419 |
12 | 28b54b41aa45 |
13 | 11a549917765 |
14 | 70a87728885 |
15 | 3812349a1c8 |
hex | 1db13b8fa55 |
2040440355413 has 2 divisors, whose sum is σ = 2040440355414. Its totient is φ = 2040440355412.
The previous prime is 2040440355281. The next prime is 2040440355419. The reversal of 2040440355413 is 3145530440402.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1413820877764 + 626619477649 = 1189042^2 + 791593^2 .
It is a cyclic number.
It is not a de Polignac number, because 2040440355413 - 28 = 2040440355157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2040440355419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1020220177706 + 1020220177707.
It is an arithmetic number, because the mean of its divisors is an integer number (1020220177707).
Almost surely, 22040440355413 is an apocalyptic number.
It is an amenable number.
2040440355413 is a deficient number, since it is larger than the sum of its proper divisors (1).
2040440355413 is an equidigital number, since it uses as much as digits as its factorization.
2040440355413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 35.
Adding to 2040440355413 its reverse (3145530440402), we get a palindrome (5185970795815).
The spelling of 2040440355413 in words is "two trillion, forty billion, four hundred forty million, three hundred fifty-five thousand, four hundred thirteen".
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