Base | Representation |
---|---|
bin | 101110011010011001011000… |
… | …101010000110011010010011 |
3 | 222202202001222201021112022121 |
4 | 232122121120222012122103 |
5 | 203223332130401003021 |
6 | 2002045152440315111 |
7 | 60665323364523364 |
oct | 5632313052063223 |
9 | 882661881245277 |
10 | 204124103141011 |
11 | 5a04960079a669 |
12 | 1aa88751172a97 |
13 | 89b8a88366761 |
14 | 38599331cbb6b |
15 | 188eb0a34a741 |
hex | b9a658a86693 |
204124103141011 has 2 divisors, whose sum is σ = 204124103141012. Its totient is φ = 204124103141010.
The previous prime is 204124103140981. The next prime is 204124103141017. The reversal of 204124103141011 is 110141301421402.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 204124103141011 - 213 = 204124103132819 is a prime.
It is a super-3 number, since 3×2041241031410113 (a number of 44 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (204124103141017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102062051570505 + 102062051570506.
It is an arithmetic number, because the mean of its divisors is an integer number (102062051570506).
Almost surely, 2204124103141011 is an apocalyptic number.
204124103141011 is a deficient number, since it is larger than the sum of its proper divisors (1).
204124103141011 is an equidigital number, since it uses as much as digits as its factorization.
204124103141011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 204124103141011 its reverse (110141301421402), we get a palindrome (314265404562413).
The spelling of 204124103141011 in words is "two hundred four trillion, one hundred twenty-four billion, one hundred three million, one hundred forty-one thousand, eleven".
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