Base | Representation |
---|---|
bin | 1011111000110110111… |
… | …0000000110011100101 |
3 | 201112011220200111211111 |
4 | 2332031232000303211 |
5 | 11321241211043133 |
6 | 233454351505021 |
7 | 20520166544611 |
oct | 2761556006345 |
9 | 645156614744 |
10 | 204241112293 |
11 | 79688868689 |
12 | 336bbb28171 |
13 | 1634bb90a8a |
14 | 9c5747a341 |
15 | 54a59751cd |
hex | 2f8db80ce5 |
204241112293 has 2 divisors, whose sum is σ = 204241112294. Its totient is φ = 204241112292.
The previous prime is 204241112239. The next prime is 204241112321. The reversal of 204241112293 is 392211142402.
Together with previous prime (204241112239) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 151689217729 + 52551894564 = 389473^2 + 229242^2 .
It is a cyclic number.
It is not a de Polignac number, because 204241112293 - 217 = 204240981221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (204241112233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102120556146 + 102120556147.
It is an arithmetic number, because the mean of its divisors is an integer number (102120556147).
Almost surely, 2204241112293 is an apocalyptic number.
It is an amenable number.
204241112293 is a deficient number, since it is larger than the sum of its proper divisors (1).
204241112293 is an equidigital number, since it uses as much as digits as its factorization.
204241112293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 204241112293 its reverse (392211142402), we get a palindrome (596452254695).
The spelling of 204241112293 in words is "two hundred four billion, two hundred forty-one million, one hundred twelve thousand, two hundred ninety-three".
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