Base | Representation |
---|---|
bin | 101110011101011101001011… |
… | …111000110110001101011111 |
3 | 222210111011122122100102002122 |
4 | 232131131023320312031133 |
5 | 203240303213112104021 |
6 | 2002325522335213155 |
7 | 61016445326064353 |
oct | 5635351370661537 |
9 | 883434578312078 |
10 | 204334342300511 |
11 | 5a11a787274955 |
12 | 1ab014459771bb |
13 | 8a02851a8b497 |
14 | 3865b990c9463 |
15 | 189531266ebab |
hex | b9d74be3635f |
204334342300511 has 2 divisors, whose sum is σ = 204334342300512. Its totient is φ = 204334342300510.
The previous prime is 204334342300489. The next prime is 204334342300577. The reversal of 204334342300511 is 115003243433402.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 204334342300511 - 210 = 204334342299487 is a prime.
It is a super-2 number, since 2×2043343423005112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (204334342306511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 102167171150255 + 102167171150256.
It is an arithmetic number, because the mean of its divisors is an integer number (102167171150256).
Almost surely, 2204334342300511 is an apocalyptic number.
204334342300511 is a deficient number, since it is larger than the sum of its proper divisors (1).
204334342300511 is an equidigital number, since it uses as much as digits as its factorization.
204334342300511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 204334342300511 its reverse (115003243433402), we get a palindrome (319337585733913).
The spelling of 204334342300511 in words is "two hundred four trillion, three hundred thirty-four billion, three hundred forty-two million, three hundred thousand, five hundred eleven".
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