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2043434131 is a prime number
BaseRepresentation
bin111100111001100…
…0101010010010011
312021102002012122121
41321303011102103
513141104343011
6534433515111
7101431621624
oct17163052223
95242065577
102043434131
11959513342
12490412a97
1326747402b
14155563a4b
15be5e1e71
hex79cc5493

2043434131 has 2 divisors, whose sum is σ = 2043434132. Its totient is φ = 2043434130.

The previous prime is 2043434123. The next prime is 2043434147. The reversal of 2043434131 is 1314343402.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2043434131 - 23 = 2043434123 is a prime.

It is a super-2 number, since 2×20434341312 = 8351246095471450322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2043434096 and 2043434105.

It is not a weakly prime, because it can be changed into another prime (2043434101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1021717065 + 1021717066.

It is an arithmetic number, because the mean of its divisors is an integer number (1021717066).

Almost surely, 22043434131 is an apocalyptic number.

2043434131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2043434131 is an equidigital number, since it uses as much as digits as its factorization.

2043434131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 2043434131 is about 45204.3596459457. The cubic root of 2043434131 is about 1268.9764069218.

Adding to 2043434131 its reverse (1314343402), we get a palindrome (3357777533).

The spelling of 2043434131 in words is "two billion, forty-three million, four hundred thirty-four thousand, one hundred thirty-one".