Base | Representation |
---|---|
bin | 1001010100110000010011… |
… | …00011001100000000010111 |
3 | 2200121012021022000211000212 |
4 | 10222120021203030000113 |
5 | 10141420334011342023 |
6 | 111335321104000035 |
7 | 4214250341040032 |
oct | 452301143140027 |
9 | 80535238024025 |
10 | 20504334090263 |
11 | 6595926057711 |
12 | 2371a6400001b |
13 | b5972032895a |
14 | 50c5b4d20019 |
15 | 258571233e78 |
hex | 12a6098cc017 |
20504334090263 has 2 divisors, whose sum is σ = 20504334090264. Its totient is φ = 20504334090262.
The previous prime is 20504334090223. The next prime is 20504334090301. The reversal of 20504334090263 is 36209043340502.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20504334090263 - 244 = 2912148045847 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20504334090263.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20504334090203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10252167045131 + 10252167045132.
It is an arithmetic number, because the mean of its divisors is an integer number (10252167045132).
Almost surely, 220504334090263 is an apocalyptic number.
20504334090263 is a deficient number, since it is larger than the sum of its proper divisors (1).
20504334090263 is an equidigital number, since it uses as much as digits as its factorization.
20504334090263 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 466560, while the sum is 41.
The spelling of 20504334090263 in words is "twenty trillion, five hundred four billion, three hundred thirty-four million, ninety thousand, two hundred sixty-three".
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