Base | Representation |
---|---|
bin | 11101110111001101110… |
… | …100001100110010110101 |
3 | 21021011222000210221122110 |
4 | 131313031310030302311 |
5 | 232110302004211430 |
6 | 4210425032121233 |
7 | 301156151463315 |
oct | 35671564146265 |
9 | 7234860727573 |
10 | 2052152413365 |
11 | 7213495a095a |
12 | 291879836219 |
13 | 11b695213972 |
14 | 71478dd1445 |
15 | 385ab7de7b0 |
hex | 1ddcdd0ccb5 |
2052152413365 has 64 divisors (see below), whose sum is σ = 3518351354880. Its totient is φ = 1017743400960.
The previous prime is 2052152413327. The next prime is 2052152413397. The reversal of 2052152413365 is 5633142512502.
It is not a de Polignac number, because 2052152413365 - 217 = 2052152282293 is a prime.
It is a super-2 number, since 2×20521524133652 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 30082195 + ... + 30150335.
It is an arithmetic number, because the mean of its divisors is an integer number (54974239920).
Almost surely, 22052152413365 is an apocalyptic number.
It is an amenable number.
2052152413365 is a deficient number, since it is larger than the sum of its proper divisors (1466198941515).
2052152413365 is a wasteful number, since it uses less digits than its factorization.
2052152413365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69582.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 2052152413365 its reverse (5633142512502), we get a palindrome (7685294925867).
The spelling of 2052152413365 in words is "two trillion, fifty-two billion, one hundred fifty-two million, four hundred thirteen thousand, three hundred sixty-five".
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