Base | Representation |
---|---|
bin | 11101111000100111111… |
… | …011010001000001100101 |
3 | 21021022212101112102210211 |
4 | 131320213323101001211 |
5 | 232121401014341031 |
6 | 4211235035215421 |
7 | 301241466543550 |
oct | 35704773210145 |
9 | 7238771472724 |
10 | 2053664215141 |
11 | 721a54a01a10 |
12 | 29201bba7571 |
13 | 11b8764a8926 |
14 | 7157dac7697 |
15 | 386493babb1 |
hex | 1de27ed1065 |
2053664215141 has 64 divisors (see below), whose sum is σ = 2641496126976. Its totient is φ = 1550159769600.
The previous prime is 2053664215123. The next prime is 2053664215199. The reversal of 2053664215141 is 1415124663502.
It is a cyclic number.
It is not a de Polignac number, because 2053664215141 - 213 = 2053664206949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2053664215094 and 2053664215103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2053664212141) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 511750851 + ... + 511754863.
It is an arithmetic number, because the mean of its divisors is an integer number (41273376984).
Almost surely, 22053664215141 is an apocalyptic number.
It is an amenable number.
2053664215141 is a deficient number, since it is larger than the sum of its proper divisors (587831911835).
2053664215141 is a wasteful number, since it uses less digits than its factorization.
2053664215141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5182.
The product of its (nonzero) digits is 172800, while the sum is 40.
Adding to 2053664215141 its reverse (1415124663502), we get a palindrome (3468788878643).
The spelling of 2053664215141 in words is "two trillion, fifty-three billion, six hundred sixty-four million, two hundred fifteen thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •