Base | Representation |
---|---|
bin | 1001011000101111000100… |
… | …10011111011010000010011 |
3 | 2201002021022202221022211202 |
4 | 10230113202103323100103 |
5 | 10201141000332402124 |
6 | 111522221443501415 |
7 | 4230162031230611 |
oct | 454274223732023 |
9 | 81067282838752 |
10 | 20641114731539 |
11 | 6638936175a05 |
12 | 239447768786b |
13 | b695aac31853 |
14 | 51506cb646b1 |
15 | 25bdc94d15ae |
hex | 12c5e24fb413 |
20641114731539 has 2 divisors, whose sum is σ = 20641114731540. Its totient is φ = 20641114731538.
The previous prime is 20641114731487. The next prime is 20641114731547. The reversal of 20641114731539 is 93513741114602.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20641114731539 - 28 = 20641114731283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20641114731493 and 20641114731502.
It is not a weakly prime, because it can be changed into another prime (20641114031539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10320557365769 + 10320557365770.
It is an arithmetic number, because the mean of its divisors is an integer number (10320557365770).
Almost surely, 220641114731539 is an apocalyptic number.
20641114731539 is a deficient number, since it is larger than the sum of its proper divisors (1).
20641114731539 is an equidigital number, since it uses as much as digits as its factorization.
20641114731539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 47.
The spelling of 20641114731539 in words is "twenty trillion, six hundred forty-one billion, one hundred fourteen million, seven hundred thirty-one thousand, five hundred thirty-nine".
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