210001201110011 has 2 divisors, whose sum is σ = 210001201110012. Its totient is φ = 210001201110010.

The previous prime is 210001201110007. The next prime is 210001201110013. The reversal of 210001201110011 is 110011102100012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 210001201110011 - 2² = 210001201110007 is a prime.

Together with 210001201110013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 210001201109974 and 210001201110001.

It is not a weakly prime, because it can be changed into another prime (210001201110013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (37) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105000600555005 + 105000600555006.

It is an arithmetic number, because the mean of its divisors is an integer number (105000600555006).

Almost surely, 2^{210001201110011} is an apocalyptic number.

210001201110011 is a deficient number, since it is larger than the sum of its proper divisors (1).

210001201110011 is an equidigital number, since it uses as much as digits as its factorization.

210001201110011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 210001201110011 its reverse (110011102100012), we get a palindrome (320012303210023).

Subtracting from 210001201110011 its reverse (110011102100012), we obtain a palindrome (99990099009999).

The spelling of 210001201110011 in words is "two hundred ten trillion, one billion, two hundred one million, one hundred ten thousand, eleven".