Base | Representation |
---|---|
bin | 11110100011110111101… |
… | …101110100011101000101 |
3 | 21102202201120200221112022 |
4 | 132203313231310131011 |
5 | 233402001101233013 |
6 | 4244434515532525 |
7 | 304504302446066 |
oct | 36436755643505 |
9 | 7382646627468 |
10 | 2100100024133 |
11 | 73a713794561 |
12 | 29b01b2ba145 |
13 | 1230669c5597 |
14 | 73906d0a56d |
15 | 39965dc4008 |
hex | 1e8f7b74745 |
2100100024133 has 2 divisors, whose sum is σ = 2100100024134. Its totient is φ = 2100100024132.
The previous prime is 2100100024079. The next prime is 2100100024157. The reversal of 2100100024133 is 3314200010012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1484162300644 + 615937723489 = 1218262^2 + 784817^2 .
It is a cyclic number.
It is not a de Polignac number, because 2100100024133 - 224 = 2100083246917 is a prime.
It is a super-2 number, since 2×21001000241332 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2100100024933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050050012066 + 1050050012067.
It is an arithmetic number, because the mean of its divisors is an integer number (1050050012067).
Almost surely, 22100100024133 is an apocalyptic number.
It is an amenable number.
2100100024133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100100024133 is an equidigital number, since it uses as much as digits as its factorization.
2100100024133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 2100100024133 its reverse (3314200010012), we get a palindrome (5414300034145).
The spelling of 2100100024133 in words is "two trillion, one hundred billion, one hundred million, twenty-four thousand, one hundred thirty-three".
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