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2100109924949 is a prime number
BaseRepresentation
bin11110100011111000010…
…011100101101001010101
321102202202021022221220012
4132203320103211221111
5233402011120044244
64244435512050005
7304504452553331
oct36437023455125
97382667287805
102100109924949
1173a719337153
1229b022693905
13123068a80c5a
14739083667c1
1539966bcc89e
hex1e8f84e5a55

2100109924949 has 2 divisors, whose sum is σ = 2100109924950. Its totient is φ = 2100109924948.

The previous prime is 2100109924903. The next prime is 2100109924961. The reversal of 2100109924949 is 9494299010012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1349256480625 + 750853444324 = 1161575^2 + 866518^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2100109924949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2100109924897 and 2100109924906.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2100109924999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050054962474 + 1050054962475.

It is an arithmetic number, because the mean of its divisors is an integer number (1050054962475).

Almost surely, 22100109924949 is an apocalyptic number.

It is an amenable number.

2100109924949 is a deficient number, since it is larger than the sum of its proper divisors (1).

2100109924949 is an equidigital number, since it uses as much as digits as its factorization.

2100109924949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 419904, while the sum is 50.

The spelling of 2100109924949 in words is "two trillion, one hundred billion, one hundred nine million, nine hundred twenty-four thousand, nine hundred forty-nine".