Base | Representation |
---|---|
bin | 11110100011111000011… |
… | …011100011001100001011 |
3 | 21102202202102020222211222 |
4 | 132203320123203030023 |
5 | 233402012133341133 |
6 | 4244440024512255 |
7 | 304504506365213 |
oct | 36437033431413 |
9 | 7382672228758 |
10 | 2100112012043 |
11 | 73a71a532221 |
12 | 29b02331b68b |
13 | 123069331c16 |
14 | 7390874b243 |
15 | 39966e90e98 |
hex | 1e8f86e330b |
2100112012043 has 2 divisors, whose sum is σ = 2100112012044. Its totient is φ = 2100112012042.
The previous prime is 2100112011971. The next prime is 2100112012051. The reversal of 2100112012043 is 3402102110012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2100112012043 - 216 = 2100111946507 is a prime.
It is not a weakly prime, because it can be changed into another prime (2100112012343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050056006021 + 1050056006022.
It is an arithmetic number, because the mean of its divisors is an integer number (1050056006022).
Almost surely, 22100112012043 is an apocalyptic number.
2100112012043 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100112012043 is an equidigital number, since it uses as much as digits as its factorization.
2100112012043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2100112012043 its reverse (3402102110012), we get a palindrome (5502214122055).
The spelling of 2100112012043 in words is "two trillion, one hundred billion, one hundred twelve million, twelve thousand, forty-three".
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