Base | Representation |
---|---|
bin | 11110100011111000111… |
… | …010011010010011110011 |
3 | 21102202202222111000100212 |
4 | 132203320322122103303 |
5 | 233402021221232011 |
6 | 4244440514134335 |
7 | 304504635221402 |
oct | 36437072322363 |
9 | 7382688430325 |
10 | 2100120102131 |
11 | 73a724058447 |
12 | 29b025b813ab |
13 | 12306ac0535c |
14 | 73909855639 |
15 | 39967a3d08b |
hex | 1e8f8e9a4f3 |
2100120102131 has 2 divisors, whose sum is σ = 2100120102132. Its totient is φ = 2100120102130.
The previous prime is 2100120102079. The next prime is 2100120102137. The reversal of 2100120102131 is 1312010210012.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2100120102131 is a prime.
It is a super-2 number, since 2×21001201021312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2100120102137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050060051065 + 1050060051066.
It is an arithmetic number, because the mean of its divisors is an integer number (1050060051066).
Almost surely, 22100120102131 is an apocalyptic number.
2100120102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100120102131 is an equidigital number, since it uses as much as digits as its factorization.
2100120102131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 2100120102131 its reverse (1312010210012), we get a palindrome (3412130312143).
The spelling of 2100120102131 in words is "two trillion, one hundred billion, one hundred twenty million, one hundred two thousand, one hundred thirty-one".
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