Base | Representation |
---|---|
bin | 11110100011111000111… |
… | …010011100101101011111 |
3 | 21102202202222111111212011 |
4 | 132203320322130231133 |
5 | 233402021222040332 |
6 | 4244440514252051 |
7 | 304504635262153 |
oct | 36437072345537 |
9 | 7382688444764 |
10 | 2100120111967 |
11 | 73a724064879 |
12 | 29b025b87027 |
13 | 12306ac09987 |
14 | 73909859063 |
15 | 39967a40e47 |
hex | 1e8f8e9cb5f |
2100120111967 has 2 divisors, whose sum is σ = 2100120111968. Its totient is φ = 2100120111966.
The previous prime is 2100120111959. The next prime is 2100120112061. The reversal of 2100120111967 is 7691110210012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2100120111967 - 23 = 2100120111959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2100120111937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050060055983 + 1050060055984.
It is an arithmetic number, because the mean of its divisors is an integer number (1050060055984).
Almost surely, 22100120111967 is an apocalyptic number.
2100120111967 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100120111967 is an equidigital number, since it uses as much as digits as its factorization.
2100120111967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 31.
Adding to 2100120111967 its reverse (7691110210012), we get a palindrome (9791230321979).
The spelling of 2100120111967 in words is "two trillion, one hundred billion, one hundred twenty million, one hundred eleven thousand, nine hundred sixty-seven".
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