Base | Representation |
---|---|
bin | 11110100011111001000… |
… | …010000100100010000001 |
3 | 21102202210010021000202101 |
4 | 132203321002010202001 |
5 | 233402022230010311 |
6 | 4244441025150401 |
7 | 304504661253442 |
oct | 36437102044201 |
9 | 7382703230671 |
10 | 2100122110081 |
11 | 73a7251aa006 |
12 | 29b02678b401 |
13 | 12306b4592a8 |
14 | 73909c192c9 |
15 | 39967cd7ec1 |
hex | 1e8f9084881 |
2100122110081 has 2 divisors, whose sum is σ = 2100122110082. Its totient is φ = 2100122110080.
The previous prime is 2100122110043. The next prime is 2100122110133. The reversal of 2100122110081 is 1800112210012.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1820192231025 + 279929879056 = 1349145^2 + 529084^2 .
It is a cyclic number.
It is not a de Polignac number, because 2100122110081 - 223 = 2100113721473 is a prime.
It is a super-2 number, since 2×21001221100812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2100122110381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050061055040 + 1050061055041.
It is an arithmetic number, because the mean of its divisors is an integer number (1050061055041).
Almost surely, 22100122110081 is an apocalyptic number.
It is an amenable number.
2100122110081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100122110081 is an equidigital number, since it uses as much as digits as its factorization.
2100122110081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 2100122110081 its reverse (1800112210012), we get a palindrome (3900234320093).
The spelling of 2100122110081 in words is "two trillion, one hundred billion, one hundred twenty-two million, one hundred ten thousand, eighty-one".
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