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210013122013 is a prime number
BaseRepresentation
bin1100001110010111000…
…0011110110111011101
3202002002011201222122021
43003211300132313131
511420101324401023
6240251222020141
721113215040362
oct3034560366735
9662064658567
10210013122013
118107aa28a52
1234850b77651
1316a5b952246
14a243c9c469
1556e257535d
hex30e5c1eddd

210013122013 has 2 divisors, whose sum is σ = 210013122014. Its totient is φ = 210013122012.

The previous prime is 210013121917. The next prime is 210013122023. The reversal of 210013122013 is 310221310012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 170228032569 + 39785089444 = 412587^2 + 199462^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-210013122013 is a prime.

It is a super-3 number, since 3×2100131220133 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (210013122023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105006561006 + 105006561007.

It is an arithmetic number, because the mean of its divisors is an integer number (105006561007).

Almost surely, 2210013122013 is an apocalyptic number.

It is an amenable number.

210013122013 is a deficient number, since it is larger than the sum of its proper divisors (1).

210013122013 is an equidigital number, since it uses as much as digits as its factorization.

210013122013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 210013122013 its reverse (310221310012), we get a palindrome (520234432025).

The spelling of 210013122013 in words is "two hundred ten billion, thirteen million, one hundred twenty-two thousand, thirteen".