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2100209809597 is a prime number
BaseRepresentation
bin11110100011111110010…
…000100111100010111101
321102210000020021121212121
4132203332100213202331
5233402212202401342
64244453441002541
7304510104555244
oct36437620474275
97383006247777
102100209809597
1173a76a759a49
1229b050023451
131230836840b3
147391772795b
153997085d067
hex1e8fe4278bd

2100209809597 has 2 divisors, whose sum is σ = 2100209809598. Its totient is φ = 2100209809596.

The previous prime is 2100209809591. The next prime is 2100209809639. The reversal of 2100209809597 is 7959089020012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1596548494116 + 503661315481 = 1263546^2 + 709691^2 .

It is a cyclic number.

It is not a de Polignac number, because 2100209809597 - 23 = 2100209809589 is a prime.

It is a super-4 number, since 4×21002098095974 (a number of 50 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2100209809591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050104904798 + 1050104904799.

It is an arithmetic number, because the mean of its divisors is an integer number (1050104904799).

Almost surely, 22100209809597 is an apocalyptic number.

It is an amenable number.

2100209809597 is a deficient number, since it is larger than the sum of its proper divisors (1).

2100209809597 is an equidigital number, since it uses as much as digits as its factorization.

2100209809597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 816480, while the sum is 52.

The spelling of 2100209809597 in words is "two trillion, one hundred billion, two hundred nine million, eight hundred nine thousand, five hundred ninety-seven".