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210021200009953 is a prime number
BaseRepresentation
bin101111110000001101011111…
…000001011001101011100001
31000112121211102112102101211121
4233300031133001121223201
5210011441404200304303
62022402223552212241
762144350060045243
oct5760153701315341
91015554375371747
10210021200009953
1160a12544189652
121b67b622b3a081
139025bb65bab97
1439c111a56c093
15194320028b9bd
hexbf035f059ae1

210021200009953 has 2 divisors, whose sum is σ = 210021200009954. Its totient is φ = 210021200009952.

The previous prime is 210021200009941. The next prime is 210021200010047. The reversal of 210021200009953 is 359900002120012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 150798817520289 + 59222382489664 = 12280017^2 + 7695608^2 .

It is a cyclic number.

It is not a de Polignac number, because 210021200009953 - 225 = 210021166455521 is a prime.

It is a super-3 number, since 3×2100212000099533 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (210021200009923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105010600004976 + 105010600004977.

It is an arithmetic number, because the mean of its divisors is an integer number (105010600004977).

Almost surely, 2210021200009953 is an apocalyptic number.

It is an amenable number.

210021200009953 is a deficient number, since it is larger than the sum of its proper divisors (1).

210021200009953 is an equidigital number, since it uses as much as digits as its factorization.

210021200009953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 34.

Adding to 210021200009953 its reverse (359900002120012), we get a palindrome (569921202129965).

The spelling of 210021200009953 in words is "two hundred ten trillion, twenty-one billion, two hundred million, nine thousand, nine hundred fifty-three".