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21002221119983 is a prime number
BaseRepresentation
bin1001100011001111101011…
…11011011110100111101111
32202100210101220022111221212
410301213311323132213233
510223100022101314413
6112400142010545035
74265234422002245
oct461476573364757
982323356274855
1021002221119983
116767aa0328284
12243245543817b
13b9466879704c
1452872767c795
152664b15dbca8
hex1319f5ede9ef

21002221119983 has 2 divisors, whose sum is σ = 21002221119984. Its totient is φ = 21002221119982.

The previous prime is 21002221119967. The next prime is 21002221120019. The reversal of 21002221119983 is 38991112220012.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21002221119983 - 24 = 21002221119967 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21002221119983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21002221119083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10501110559991 + 10501110559992.

It is an arithmetic number, because the mean of its divisors is an integer number (10501110559992).

Almost surely, 221002221119983 is an apocalyptic number.

21002221119983 is a deficient number, since it is larger than the sum of its proper divisors (1).

21002221119983 is an equidigital number, since it uses as much as digits as its factorization.

21002221119983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 41.

Adding to 21002221119983 its reverse (38991112220012), we get a palindrome (59993333339995).

The spelling of 21002221119983 in words is "twenty-one trillion, two billion, two hundred twenty-one million, one hundred nineteen thousand, nine hundred eighty-three".