Base | Representation |
---|---|
bin | 1001100011001111101011… |
… | …11011011110100111101111 |
3 | 2202100210101220022111221212 |
4 | 10301213311323132213233 |
5 | 10223100022101314413 |
6 | 112400142010545035 |
7 | 4265234422002245 |
oct | 461476573364757 |
9 | 82323356274855 |
10 | 21002221119983 |
11 | 6767aa0328284 |
12 | 243245543817b |
13 | b9466879704c |
14 | 52872767c795 |
15 | 2664b15dbca8 |
hex | 1319f5ede9ef |
21002221119983 has 2 divisors, whose sum is σ = 21002221119984. Its totient is φ = 21002221119982.
The previous prime is 21002221119967. The next prime is 21002221120019. The reversal of 21002221119983 is 38991112220012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21002221119983 - 24 = 21002221119967 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21002221119983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21002221119083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10501110559991 + 10501110559992.
It is an arithmetic number, because the mean of its divisors is an integer number (10501110559992).
Almost surely, 221002221119983 is an apocalyptic number.
21002221119983 is a deficient number, since it is larger than the sum of its proper divisors (1).
21002221119983 is an equidigital number, since it uses as much as digits as its factorization.
21002221119983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 41.
Adding to 21002221119983 its reverse (38991112220012), we get a palindrome (59993333339995).
The spelling of 21002221119983 in words is "twenty-one trillion, two billion, two hundred twenty-one million, one hundred nineteen thousand, nine hundred eighty-three".
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