Base | Representation |
---|---|
bin | 1001100011010001010110… |
… | …00010101110101010100111 |
3 | 2202100212201000001201222211 |
4 | 10301220223002232222213 |
5 | 10223103333211310114 |
6 | 112400410242104251 |
7 | 4265265462113446 |
oct | 461505302565247 |
9 | 82325630051884 |
10 | 21003112213159 |
11 | 676840832681a |
12 | 243266394b087 |
13 | b9477b29260b |
14 | 5287adb5ad5d |
15 | 2665149596c4 |
hex | 131a2b0aeaa7 |
21003112213159 has 2 divisors, whose sum is σ = 21003112213160. Its totient is φ = 21003112213158.
The previous prime is 21003112213099. The next prime is 21003112213177. The reversal of 21003112213159 is 95131221130012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21003112213159 - 217 = 21003112082087 is a prime.
It is a super-2 number, since 2×210031122131592 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21003112213159.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21003112213189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10501556106579 + 10501556106580.
It is an arithmetic number, because the mean of its divisors is an integer number (10501556106580).
Almost surely, 221003112213159 is an apocalyptic number.
21003112213159 is a deficient number, since it is larger than the sum of its proper divisors (1).
21003112213159 is an equidigital number, since it uses as much as digits as its factorization.
21003112213159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 31.
The spelling of 21003112213159 in words is "twenty-one trillion, three billion, one hundred twelve million, two hundred thirteen thousand, one hundred fifty-nine".
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