Base | Representation |
---|---|
bin | 1100001110011011010… |
… | …1110111100100100111 |
3 | 202002010102222002102202 |
4 | 3003212311313210213 |
5 | 11420121003424033 |
6 | 240253111525115 |
7 | 21113525455043 |
oct | 3034665674447 |
9 | 662112862382 |
10 | 210031311143 |
11 | 8108a221795 |
12 | 3485708979b |
13 | 16a62650344 |
14 | a246475023 |
15 | 56e3e698e8 |
hex | 30e6d77927 |
210031311143 has 2 divisors, whose sum is σ = 210031311144. Its totient is φ = 210031311142.
The previous prime is 210031311121. The next prime is 210031311199. The reversal of 210031311143 is 341113130012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 210031311143 - 210 = 210031310119 is a prime.
It is a super-2 number, since 2×2100313111432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210031311443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105015655571 + 105015655572.
It is an arithmetic number, because the mean of its divisors is an integer number (105015655572).
Almost surely, 2210031311143 is an apocalyptic number.
210031311143 is a deficient number, since it is larger than the sum of its proper divisors (1).
210031311143 is an equidigital number, since it uses as much as digits as its factorization.
210031311143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 210031311143 its reverse (341113130012), we get a palindrome (551144441155).
The spelling of 210031311143 in words is "two hundred ten billion, thirty-one million, three hundred eleven thousand, one hundred forty-three".
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