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2100344329981 is a prime number
BaseRepresentation
bin11110100100000110010…
…001110001011011111101
321102210100121101222011001
4132210012101301123331
5233403001122024411
64244515044130301
7304513330144042
oct36440621613375
97383317358131
102100344329981
1173a829689117
1229b089096991
131230a54c3261
147392b5431c9
153997c580dc1
hex1e9064716fd

2100344329981 has 2 divisors, whose sum is σ = 2100344329982. Its totient is φ = 2100344329980.

The previous prime is 2100344329969. The next prime is 2100344330047. The reversal of 2100344329981 is 1899234430012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1082785924900 + 1017558405081 = 1040570^2 + 1008741^2 .

It is a cyclic number.

It is not a de Polignac number, because 2100344329981 - 29 = 2100344329469 is a prime.

It is a super-2 number, since 2×21003443299812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2100344329381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050172164990 + 1050172164991.

It is an arithmetic number, because the mean of its divisors is an integer number (1050172164991).

Almost surely, 22100344329981 is an apocalyptic number.

It is an amenable number.

2100344329981 is a deficient number, since it is larger than the sum of its proper divisors (1).

2100344329981 is an equidigital number, since it uses as much as digits as its factorization.

2100344329981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 373248, while the sum is 46.

Adding to 2100344329981 its reverse (1899234430012), we get a palindrome (3999578759993).

The spelling of 2100344329981 in words is "two trillion, one hundred billion, three hundred forty-four million, three hundred twenty-nine thousand, nine hundred eighty-one".