Base | Representation |
---|---|
bin | 1001100011011110001100… |
… | …10011010111111001100101 |
3 | 2202101112111212020211210222 |
4 | 10301233012103113321211 |
5 | 10223212001033342013 |
6 | 112403511040454125 |
7 | 4265631453332444 |
oct | 461570623277145 |
9 | 82345455224728 |
10 | 21010012012133 |
11 | 6770329061921 |
12 | 2433a6a61a345 |
13 | b9530a8b43c1 |
14 | 528c66272d5b |
15 | 2667ba57e508 |
hex | 131bc64d7e65 |
21010012012133 has 2 divisors, whose sum is σ = 21010012012134. Its totient is φ = 21010012012132.
The previous prime is 21010012012117. The next prime is 21010012012159. The reversal of 21010012012133 is 33121021001012.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16551740234689 + 4458271777444 = 4068383^2 + 2111462^2 .
It is a cyclic number.
It is not a de Polignac number, because 21010012012133 - 24 = 21010012012117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21010012012433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10505006006066 + 10505006006067.
It is an arithmetic number, because the mean of its divisors is an integer number (10505006006067).
Almost surely, 221010012012133 is an apocalyptic number.
It is an amenable number.
21010012012133 is a deficient number, since it is larger than the sum of its proper divisors (1).
21010012012133 is an equidigital number, since it uses as much as digits as its factorization.
21010012012133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 21010012012133 its reverse (33121021001012), we get a palindrome (54131033013145).
The spelling of 21010012012133 in words is "twenty-one trillion, ten billion, twelve million, twelve thousand, one hundred thirty-three".
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