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210101000113 is a prime number
BaseRepresentation
bin1100001110101011111…
…1101101011110110001
3202002022022002122201201
43003222333231132301
511420241324000423
6240304041331201
721115333014634
oct3035277553661
9662268078651
10210101000113
11811155a0084
1234876496b01
1316a73c10414
14a251815c1b
1556ea1332ad
hex30eafed7b1

210101000113 has 2 divisors, whose sum is σ = 210101000114. Its totient is φ = 210101000112.

The previous prime is 210101000101. The next prime is 210101000147. The reversal of 210101000113 is 311000101012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 173141706609 + 36959293504 = 416103^2 + 192248^2 .

It is a cyclic number.

It is not a de Polignac number, because 210101000113 - 233 = 201511065521 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 210101000113.

It is not a weakly prime, because it can be changed into another prime (210101010113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105050500056 + 105050500057.

It is an arithmetic number, because the mean of its divisors is an integer number (105050500057).

Almost surely, 2210101000113 is an apocalyptic number.

It is an amenable number.

210101000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

210101000113 is an equidigital number, since it uses as much as digits as its factorization.

210101000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 210101000113 its reverse (311000101012), we get a palindrome (521101101125).

The spelling of 210101000113 in words is "two hundred ten billion, one hundred one million, one hundred thirteen", and thus it is an aban number.