Base | Representation |
---|---|
bin | 111110100111011… |
… | …0101001111110001 |
3 | 12102102110220012111 |
4 | 1331032311033301 |
5 | 13300331240423 |
6 | 544252325321 |
7 | 103031355244 |
oct | 17516651761 |
9 | 5372426174 |
10 | 2101040113 |
11 | 988a89597 |
12 | 4a7773841 |
13 | 276393403 |
14 | 15d07b25b |
15 | c46c060d |
hex | 7d3b53f1 |
2101040113 has 2 divisors, whose sum is σ = 2101040114. Its totient is φ = 2101040112.
The previous prime is 2101040101. The next prime is 2101040129. The reversal of 2101040113 is 3110401012.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2034731664 + 66308449 = 45108^2 + 8143^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2101040113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2101040093 and 2101040102.
It is not a weakly prime, because it can be changed into another prime (2101040143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050520056 + 1050520057.
It is an arithmetic number, because the mean of its divisors is an integer number (1050520057).
Almost surely, 22101040113 is an apocalyptic number.
It is an amenable number.
2101040113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2101040113 is an equidigital number, since it uses as much as digits as its factorization.
2101040113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 2101040113 is about 45837.1041079168. The cubic root of 2101040113 is about 1280.7905502568.
Adding to 2101040113 its reverse (3110401012), we get a palindrome (5211441125).
The spelling of 2101040113 in words is "two billion, one hundred one million, forty thousand, one hundred thirteen".
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