Base | Representation |
---|---|
bin | 11110100100110100000… |
… | …010101100111010011111 |
3 | 21102212100010011022110101 |
4 | 132210310002230322133 |
5 | 233411034201144411 |
6 | 4245123152521531 |
7 | 304541342303461 |
oct | 36446402547237 |
9 | 7385303138411 |
10 | 2101112131231 |
11 | 740093027603 |
12 | 29b2622502a7 |
13 | 1231985b1419 |
14 | 739a14ca131 |
15 | 399c4b978c1 |
hex | 1e9340ace9f |
2101112131231 has 2 divisors, whose sum is σ = 2101112131232. Its totient is φ = 2101112131230.
The previous prime is 2101112131193. The next prime is 2101112131249. The reversal of 2101112131231 is 1321312111012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2101112131231 - 223 = 2101103742623 is a prime.
It is a super-2 number, since 2×21011121312312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2101112131199 and 2101112131208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2101112135231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050556065615 + 1050556065616.
It is an arithmetic number, because the mean of its divisors is an integer number (1050556065616).
Almost surely, 22101112131231 is an apocalyptic number.
2101112131231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2101112131231 is an equidigital number, since it uses as much as digits as its factorization.
2101112131231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 2101112131231 its reverse (1321312111012), we get a palindrome (3422424242243).
The spelling of 2101112131231 in words is "two trillion, one hundred one billion, one hundred twelve million, one hundred thirty-one thousand, two hundred thirty-one".
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