210112101131321 has 2 divisors, whose sum is σ = 210112101131322. Its totient is φ = 210112101131320.

The previous prime is 210112101131299. The next prime is 210112101131323. The reversal of 210112101131321 is 123131101211012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 207682368393721 + 2429732737600 = 14411189^2 + 1558760^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-210112101131321 is a prime.

Together with 210112101131323, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 210112101131293 and 210112101131302.

It is not a weakly prime, because it can be changed into another prime (210112101131323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105056050565660 + 105056050565661.

It is an arithmetic number, because the mean of its divisors is an integer number (105056050565661).

Almost surely, 2^{210112101131321} is an apocalyptic number.

It is an amenable number.

210112101131321 is a deficient number, since it is larger than the sum of its proper divisors (1).

210112101131321 is an equidigital number, since it uses as much as digits as its factorization.

210112101131321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 210112101131321 its reverse (123131101211012), we get a palindrome (333243202342333).

The spelling of 210112101131321 in words is "two hundred ten trillion, one hundred twelve billion, one hundred one million, one hundred thirty-one thousand, three hundred twenty-one".