2101222143131 has 2 divisors, whose sum is σ = 2101222143132. Its totient is φ = 2101222143130.

The previous prime is 2101222143079. The next prime is 2101222143133. The reversal of 2101222143131 is 1313412221012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2101222143131 - 2⁶ = 2101222143067 is a prime.

It is a super-2 number, since 2×2101222143131² (a number of 25 digits) contains 22 as substring.

Together with 2101222143133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2101222143097 and 2101222143106.

It is not a weakly prime, because it can be changed into another prime (2101222143133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050611071565 + 1050611071566.

It is an arithmetic number, because the mean of its divisors is an integer number (1050611071566).

Almost surely, 2^{2101222143131} is an apocalyptic number.

2101222143131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2101222143131 is an equidigital number, since it uses as much as digits as its factorization.

2101222143131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2101222143131 its reverse (1313412221012), we get a palindrome (3414634364143).

The spelling of 2101222143131 in words is "two trillion, one hundred one billion, two hundred twenty-two million, one hundred forty-three thousand, one hundred thirty-one".