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210202202013 = 3151464022521
BaseRepresentation
bin1100001111000100000…
…1110000111110011101
3202002120100112020122020
43003301001300332131
511420443230431023
6240322054410353
721121002144126
oct3036101607635
9662510466566
10210202202013
1181167732611
12348a43609b9
1316a8bb84cbb
14a26103b04d
155703e73de3
hex30f1070f9d

210202202013 has 8 divisors (see below), whose sum is σ = 282125693376. Its totient is φ = 139206756000.

The previous prime is 210202201973. The next prime is 210202202017. The reversal of 210202202013 is 310202202012.

It is a happy number.

210202202013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 210202202013 - 28 = 210202201757 is a prime.

It is a super-3 number, since 3×2102022020133 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 210202201983 and 210202202001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (210202202017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 232010808 + ... + 232011713.

It is an arithmetic number, because the mean of its divisors is an integer number (35265711672).

Almost surely, 2210202202013 is an apocalyptic number.

It is an amenable number.

210202202013 is a deficient number, since it is larger than the sum of its proper divisors (71923491363).

210202202013 is a wasteful number, since it uses less digits than its factorization.

210202202013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 464022675.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 210202202013 its reverse (310202202012), we get a palindrome (520404404025).

Subtracting 210202202013 from its reverse (310202202012), we obtain a palindrome (99999999999).

The spelling of 210202202013 in words is "two hundred ten billion, two hundred two million, two hundred two thousand, thirteen".

Divisors: 1 3 151 453 464022521 1392067563 70067400671 210202202013