Base | Representation |
---|---|
bin | 111110101001011… |
… | …1000100001100001 |
3 | 12102111110211222211 |
4 | 1331102320201201 |
5 | 13301114231423 |
6 | 544331202121 |
7 | 103043400406 |
oct | 17522704141 |
9 | 5374424884 |
10 | 2102102113 |
11 | 989644481 |
12 | 4a7ba6341 |
13 | 276675907 |
14 | 15d2762ad |
15 | c483010d |
hex | 7d4b8861 |
2102102113 has 2 divisors, whose sum is σ = 2102102114. Its totient is φ = 2102102112.
The previous prime is 2102102081. The next prime is 2102102117. The reversal of 2102102113 is 3112012012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1817572689 + 284529424 = 42633^2 + 16868^2 .
It is a cyclic number.
It is not a de Polignac number, because 2102102113 - 25 = 2102102081 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2102102093 and 2102102102.
It is not a weakly prime, because it can be changed into another prime (2102102117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1051051056 + 1051051057.
It is an arithmetic number, because the mean of its divisors is an integer number (1051051057).
Almost surely, 22102102113 is an apocalyptic number.
It is an amenable number.
2102102113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2102102113 is an equidigital number, since it uses as much as digits as its factorization.
2102102113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 2102102113 is about 45848.6871458715. The cubic root of 2102102113 is about 1281.0063117175.
Adding to 2102102113 its reverse (3112012012), we get a palindrome (5214114125).
The spelling of 2102102113 in words is "two billion, one hundred two million, one hundred two thousand, one hundred thirteen".
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