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2104212554047 is a prime number
BaseRepresentation
bin11110100111101100110…
…101111000000100111111
321110011100012011010000001
4132213230311320010333
5233433411403212142
64250354545415131
7305011230412162
oct36475465700477
97404305133001
102104212554047
1174143414810a
1229b98863a4a7
13123570a26a36
1473bb7193ad9
1539b06e765b7
hex1e9ecd7813f

2104212554047 has 2 divisors, whose sum is σ = 2104212554048. Its totient is φ = 2104212554046.

The previous prime is 2104212553987. The next prime is 2104212554057. The reversal of 2104212554047 is 7404552124012.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2104212554047 - 211 = 2104212551999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2104212553997 and 2104212554015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2104212554057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052106277023 + 1052106277024.

It is an arithmetic number, because the mean of its divisors is an integer number (1052106277024).

Almost surely, 22104212554047 is an apocalyptic number.

2104212554047 is a deficient number, since it is larger than the sum of its proper divisors (1).

2104212554047 is an equidigital number, since it uses as much as digits as its factorization.

2104212554047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 89600, while the sum is 37.

Adding to 2104212554047 its reverse (7404552124012), we get a palindrome (9508764678059).

The spelling of 2104212554047 in words is "two trillion, one hundred four billion, two hundred twelve million, five hundred fifty-four thousand, forty-seven".