Base | Representation |
---|---|
bin | 11110100111101100110… |
… | …101111000000100111111 |
3 | 21110011100012011010000001 |
4 | 132213230311320010333 |
5 | 233433411403212142 |
6 | 4250354545415131 |
7 | 305011230412162 |
oct | 36475465700477 |
9 | 7404305133001 |
10 | 2104212554047 |
11 | 74143414810a |
12 | 29b98863a4a7 |
13 | 123570a26a36 |
14 | 73bb7193ad9 |
15 | 39b06e765b7 |
hex | 1e9ecd7813f |
2104212554047 has 2 divisors, whose sum is σ = 2104212554048. Its totient is φ = 2104212554046.
The previous prime is 2104212553987. The next prime is 2104212554057. The reversal of 2104212554047 is 7404552124012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2104212554047 - 211 = 2104212551999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2104212553997 and 2104212554015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2104212554057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052106277023 + 1052106277024.
It is an arithmetic number, because the mean of its divisors is an integer number (1052106277024).
Almost surely, 22104212554047 is an apocalyptic number.
2104212554047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2104212554047 is an equidigital number, since it uses as much as digits as its factorization.
2104212554047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 89600, while the sum is 37.
Adding to 2104212554047 its reverse (7404552124012), we get a palindrome (9508764678059).
The spelling of 2104212554047 in words is "two trillion, one hundred four billion, two hundred twelve million, five hundred fifty-four thousand, forty-seven".
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