Base | Representation |
---|---|
bin | 10011100110001101… |
… | …110001111110111111 |
3 | 2000022110200121202201 |
4 | 103212031301332333 |
5 | 321043303211341 |
6 | 13400000132331 |
7 | 1343306046526 |
oct | 234615617677 |
9 | 60273617681 |
10 | 21042241471 |
11 | 8a18884509 |
12 | 40b30070a7 |
13 | 1ca45b4974 |
14 | 10388ab4bd |
15 | 8324e3331 |
hex | 4e6371fbf |
21042241471 has 2 divisors, whose sum is σ = 21042241472. Its totient is φ = 21042241470.
The previous prime is 21042241447. The next prime is 21042241477. The reversal of 21042241471 is 17414224012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21042241471 - 25 = 21042241439 is a prime.
It is a super-3 number, since 3×210422414713 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21042241477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10521120735 + 10521120736.
It is an arithmetic number, because the mean of its divisors is an integer number (10521120736).
Almost surely, 221042241471 is an apocalyptic number.
21042241471 is a deficient number, since it is larger than the sum of its proper divisors (1).
21042241471 is an equidigital number, since it uses as much as digits as its factorization.
21042241471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3584, while the sum is 28.
Adding to 21042241471 its reverse (17414224012), we get a palindrome (38456465483).
The spelling of 21042241471 in words is "twenty-one billion, forty-two million, two hundred forty-one thousand, four hundred seventy-one".
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