Base | Representation |
---|---|
bin | 11110100111110011111… |
… | …001101101110010101001 |
3 | 21110011122110000211200021 |
4 | 132213303321231302221 |
5 | 233434132214013001 |
6 | 4250414420240441 |
7 | 305014166244445 |
oct | 36476371556251 |
9 | 7404573024607 |
10 | 2104331001001 |
11 | 741494a99059 |
12 | 29ba00240121 |
13 | 12358c428aa8 |
14 | 73bc8bc7825 |
15 | 39b12571ba1 |
hex | 1e9f3e6dca9 |
2104331001001 has 2 divisors, whose sum is σ = 2104331001002. Its totient is φ = 2104331001000.
The previous prime is 2104331000999. The next prime is 2104331001067. The reversal of 2104331001001 is 1001001334012.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2034146275225 + 70184725776 = 1426235^2 + 264924^2 .
It is a cyclic number.
It is not a de Polignac number, because 2104331001001 - 21 = 2104331000999 is a prime.
Together with 2104331000999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2104331101001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052165500500 + 1052165500501.
It is an arithmetic number, because the mean of its divisors is an integer number (1052165500501).
Almost surely, 22104331001001 is an apocalyptic number.
It is an amenable number.
2104331001001 is a deficient number, since it is larger than the sum of its proper divisors (1).
2104331001001 is an equidigital number, since it uses as much as digits as its factorization.
2104331001001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 2104331001001 its reverse (1001001334012), we get a palindrome (3105332335013).
The spelling of 2104331001001 in words is "two trillion, one hundred four billion, three hundred thirty-one million, one thousand, one".
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