Base | Representation |
---|---|
bin | 11110100111111000110… |
… | …100001010110101110000 |
3 | 21110011212012010211101200 |
4 | 132213320310022311300 |
5 | 233434314314330300 |
6 | 4250430523131200 |
7 | 305016220020531 |
oct | 36477064126560 |
9 | 7404765124350 |
10 | 2104413433200 |
11 | 741527580641 |
12 | 29ba23973b00 |
13 | 1235a352b240 |
14 | 73bd5b24688 |
15 | 39b19906200 |
hex | 1e9f8d0ad70 |
2104413433200 has 180 divisors, whose sum is σ = 7864660822200. Its totient is φ = 518009448960.
The previous prime is 2104413433183. The next prime is 2104413433223. The reversal of 2104413433200 is 23343144012.
2104413433200 is a `hidden beast` number, since 2 + 1 + 0 + 4 + 413 + 43 + 3 + 200 = 666.
It is a tau number, because it is divible by the number of its divisors (180).
It is a super-2 number, since 2×21044134332002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 22436250 + ... + 22529849.
Almost surely, 22104413433200 is an apocalyptic number.
2104413433200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2104413433200 is an abundant number, since it is smaller than the sum of its proper divisors (5760247389000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2104413433200 is a wasteful number, since it uses less digits than its factorization.
2104413433200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44966136 (or 44966122 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 2104413433200 its reverse (23343144012), we get a palindrome (2127756577212).
The spelling of 2104413433200 in words is "two trillion, one hundred four billion, four hundred thirteen million, four hundred thirty-three thousand, two hundred".
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